Proposition 2III.4.P0259 of 76 in the corpus
Patch size is the dial between detail and cost, and it is set once.
Halving the patch quadruples the tokens and multiplies attention cost sixteenfold. The choice is made at pretraining and everything afterwards inherits it.
Demonstration
For a 224 × 224 image:
/32 → 49 tokens attention cost ×1
/16 → 196 tokens ×16
/8 → 784 tokens ×256
Tokens go as the square of 1/patch, and attention goes as the square of tokens, so the bill goes as the fourth power. That is why /16 is the near-universal compromise and why /8 models are rare and expensive.
What you buy with a smaller patch is spatial resolution. A /32 model reasons about the image in 7 × 7 blocks; anything smaller than a block is averaged inside the patch embedding before layer one and is not recoverable. For classifying a scene that is fine. For a lesion a few pixels across it is the same loss described in Chapter I — a distinction destroyed at the input.
The other dial is input resolution, and it is the cheaper one. Keeping /16 and going from 224 to 448 also quadruples the tokens, but it does so by supplying more pixels rather than by dividing the same ones more finely. Book I’s Marginalia entry on EVA-CLIP is the empirical version of this: raising the resolution on the smaller model bought nearly as much as doubling the parameters.
Changing patch size after pretraining is awkward, because the patch projection and the positional embeddings are both sized to it. Changing input resolution only requires interpolating the position embeddings, which is why it is the standard move and patch size is not.
Corollary
Read /16 on a model card as a resolution ceiling. If the structure you care
about is smaller than one patch at your input size, the architecture has
already decided the answer, and no amount of fine-tuning changes it.