Md. Asif Uddin
    I.3.X02

    Softplus and its derivative

    symbolic▲△△

    Softplus is ς(z)=log⁡(1+ez)\varsigma(z) = \log(1 + e^{z}). Show that ς′(z)=σ(z)\varsigma'(z) = \sigma(z), that ς(z)>ReLU(z)\varsigma(z) > \mathrm{ReLU}(z) everywhere, and that ς(z)−ReLU(z)→0\varsigma(z) - \mathrm{ReLU}(z) \to 0 as ∣z∣→∞|z| \to \infty. Then say why softplus is nevertheless rarely used.

    Hint

    For the last part, evaluate ς\varsigma naively at z=100z = 100 in fp32.

    Solution

    The derivative. By the chain rule,

    ς′(z)=11+ez⋅ez=ez1+ez=11+e−z=σ(z)\varsigma'(z) = \frac{1}{1+e^{z}} \cdot e^{z} = \frac{e^{z}}{1+e^{z}} = \frac{1}{1+e^{-z}} = \sigma(z)

    dividing through by eze^{z} at the last step. Softplus is the antiderivative of the sigmoid — a fact worth carrying, because it means the smooth gate and the smooth rectifier are the same object seen at two orders of differentiation.

    It dominates ReLU. For z≤0z \le 0, ς(z)=log⁡(1+ez)>log⁡1=0=ReLU(z)\varsigma(z) = \log(1+e^{z}) > \log 1 = 0 = \mathrm{ReLU}(z). For z>0z > 0, write ς(z)=z+log⁡(1+e−z)>z=ReLU(z)\varsigma(z) = z + \log(1 + e^{-z}) > z = \mathrm{ReLU}(z), since the log term is positive. So ς>ReLU\varsigma > \mathrm{ReLU} everywhere.

    The gap vanishes. From the two forms above, the gap is log⁡(1+ez)\log(1+e^{z}) for z<0z<0 and log⁡(1+e−z)\log(1+e^{-z}) for z>0z>0 — in both cases log⁡(1+e−∣z∣)\log(1+e^{-|z|}), which tends to log⁡1=0\log 1 = 0. At ∣z∣=5|z| = 5 the gap is already 0.00670.0067.

    Why it is rarely used. Three reasons, in decreasing order of importance.

    It overflows if written naively. At z=100z = 100, e100=2.7×1043e^{100} = 2.7\times10^{43} — fine in fp32, but at z=800z = 800 it is ∞\infty and log⁡(∞)=∞\log(\infty) = \infty. The correct implementation is max⁡(z,0)+log⁡(1+e−∣z∣)\max(z,0) + \log(1 + e^{-|z|}) (Log-sum-exp 0.NU.02), which never overflows. Every framework does this; the point is that the naive form is a real trap.

    It costs more. Roughly 66 FLOPs per element against ReLU’s 11 — though I.3.B07 showed that difference is under 0.2%0.2\% of the layer, so this reason is weaker than it is usually stated.

    It has no exact zeros. ς(z)>0\varsigma(z) > 0 always, so no unit is ever silent and no activation is ever sparse. Sparsity was the original argument for ReLU, and whether it matters is still debated — but softplus definitively does not have it.

    What it is used for. Where a strictly positive output is required and smoothness matters: a predicted variance, a rate parameter, a scale in a distribution. Chapter I.13 uses it exactly there.

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